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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce')
| -rw-r--r-- | 534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce | 51 |
1 files changed, 51 insertions, 0 deletions
diff --git a/534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce b/534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce new file mode 100644 index 000000000..15c8fd824 --- /dev/null +++ b/534/CH11/EX11.1/11_1_Counterflow_tube_HeatX.sce @@ -0,0 +1,51 @@ +clear;
+clc;
+printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 11.1 Page 680 \n'); //Example 11.1
+// Tube Length to achieve a desired hot fluid temperature
+
+//Operating Conditions
+Tho = 60+273 ;//[K] Hot Fluid outlet Temperature
+Thi = 100+273 ; //[K] Hot Fluid intlet Temperature
+Tci = 30+273 ;//[K] Cold Fluid intlet Temperature
+mh = .1 ;//[kg/s] Hot Fluid flow rate
+mc = .2 ;//[kg/s] Cold Fluid flow rate
+Do = .045 ;//[m] Outer annulus
+Di = .025 ;//[m] Inner tube
+
+//Table A.5 Engine Oil Properties T = 353 K
+cph = 2131 ;//[J/kg.K] Specific Heat
+kh = .138 ; //[W/m.K] Conductivity
+uh = 3.25*10^-2 ; //[N.s/m^2] Viscosity
+//Table A.6 Saturated water Liquid Properties Tc = 308 K
+cpc = 4178 ;//[J/kg.K] Specific Heat
+kc = 0.625 ; //[W/m.K] Conductivity
+uc = 725*10^-6 ; //[N.s/m^2] Viscosity
+Pr = 4.85 ;//Prandtl Number
+
+q = mh*cph*(Thi-Tho);
+
+Tco = q/(mc*cpc)+Tci;
+
+T1 = Thi-Tco;
+T2 = Tho-Tci;
+Tlm = (T1-T2)/(2.30*log10(T1/T2));
+
+//Through Tube
+Ret = 4*mc/(%pi*Di*uc);
+printf("\n Flow through Tube has Reynolds Number as %i. Thus the flow is Turbulent", Ret);
+//Equation 8.60
+Nut = .023*Ret^.8*Pr^.4;
+hi = Nut*kc/Di;
+
+//Through Shell
+Reo = 4*mh*(Do-Di)/(%pi*uh*(Do^2-Di^2));
+printf("\n Flow through Tube has Reynolds Number as %i. Thus the flow is Laminar", Reo);
+//Table 8.2
+Nuo = 5.63;
+ho = Nuo*kh/(Do-Di);
+
+U = 1/[1/hi+1/ho];
+L = q/(U*%pi*Di*Tlm);
+
+printf("\n Tube Length to achieve a desired hot fluid temperature is %.1f m",L);
+//END
\ No newline at end of file |