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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /409/CH2/EX2.3 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '409/CH2/EX2.3')
| -rwxr-xr-x | 409/CH2/EX2.3/Example2_3.sce | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/409/CH2/EX2.3/Example2_3.sce b/409/CH2/EX2.3/Example2_3.sce new file mode 100755 index 000000000..c48f1ab31 --- /dev/null +++ b/409/CH2/EX2.3/Example2_3.sce @@ -0,0 +1,13 @@ +clear;
+clc;
+
+// Example 2.3
+printf('Example 2.3\n\n');
+//Page no. 46
+// Solution
+
+//Basis 7.5 g mol of NaOH
+m_NaOH = 40.0 ;//[lb]
+lb = 454 ;//[g mol]
+n = 7.50*1*m_NaOH/(lb*1);
+printf('Number of pounds of NaOH is %.3f lb.\n',n);
\ No newline at end of file |