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diff --git a/409/CH2/EX2.3/Example2_3.sce b/409/CH2/EX2.3/Example2_3.sce
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+clear;
+clc;
+
+// Example 2.3
+printf('Example 2.3\n\n');
+//Page no. 46
+// Solution
+
+//Basis 7.5 g mol of NaOH
+m_NaOH = 40.0 ;//[lb]
+lb = 454 ;//[g mol]
+n = 7.50*1*m_NaOH/(lb*1);
+printf('Number of pounds of NaOH is %.3f lb.\n',n);
+\ No newline at end of file