initial commit / add all books

9 files changed, 144 insertions, 0 deletions

diff --git a/409/CH1/EX1.1/Example1_1.sce b/409/CH1/EX1.1/Example1_1.sce
new file mode 100755
index 000000000..655abdd0c
--- /dev/null
+++ b/409/CH1/EX1.1/Example1_1.sce
@@ -0,0 +1,17 @@
+clear;

+clc;

+

+// Example 1.1

+printf('Example 1.1\n\n');

+//Page no. 13

+// Solution

+

+//(a)

+printf('(a) We cannot add the two terms since both have different dimensions. 1 foot has the dimension of the length, whereas 3 seconds has the dimension of time.\n');

+

+//(b)

+// Converting all terms to same unit

+hp = 746;//[watts]

+total = 1*hp+300;//[watts]

+

+printf(' (b) Answer is  %i watts.',total);
\ No newline at end of file
diff --git a/409/CH1/EX1.2/Example1_2.sce b/409/CH1/EX1.2/Example1_2.sce
new file mode 100755
index 000000000..89e6ea1b6
--- /dev/null
+++ b/409/CH1/EX1.2/Example1_2.sce
@@ -0,0 +1,19 @@
+clear ;

+clc;

+

+// Example 1.2

+printf('Example 1.2\n\n');

+//Page no. 17

+// Solution

+

+// (a)

+// Converting all terms to same unit

+ml = 1.61;//[km]

+km = (2*1)/(ml);//[miles]

+printf('(a) 2 kilometers is equal to %.2f miles.\n',km);

+

+//(b)

+in = 2.54;//[cm]

+dy = 24*60;//[min]

+nw_unit = (400*(in)^3*1)/(1*dy);//[cubic centimetre/min]

+printf(' (b) 400 cubic in./day is equal to %.2f cubic centimetre/min.',nw_unit);
\ No newline at end of file
diff --git a/409/CH1/EX1.3/Example1_3.sce b/409/CH1/EX1.3/Example1_3.sce
new file mode 100755
index 000000000..b6b04d331
--- /dev/null
+++ b/409/CH1/EX1.3/Example1_3.sce
@@ -0,0 +1,19 @@
+clear;

+clc;

+

+// Example 1.3

+printf('Example 1.3\n\n');

+//Page no. 17

+// Solution

+

+//(a)

+// Converting all terms to same unit

+nm = 10^(-9);//[meters]

+m1 = 10;//[decimeters]

+dm = (1.8*nm*m1)/(1*1);//[decimeters]

+printf('(a) 1.8 nanometers is equal to %.2e dm.\n',dm);

+

+//(b)

+m2 = 39.37;//[inches]

+in = (1.8*nm*m2)/(1*1);//[inches]

+printf(' (b) 1.8 nanometers is equal to %.2e in.\n',in);
\ No newline at end of file
diff --git a/409/CH1/EX1.4/Example1_4.sce b/409/CH1/EX1.4/Example1_4.sce
new file mode 100755
index 000000000..f0983ffc4
--- /dev/null
+++ b/409/CH1/EX1.4/Example1_4.sce
@@ -0,0 +1,16 @@
+clear ;

+clc;

+

+// Example 1.4

+printf('Example 1.4\n\n');

+//Page no. 19

+// Solution

+

+// Potential Energy =  mgh

+// Assume 100 lb means 100 lb mass 

+m = 100;//[lb]

+g = 32.2 ;//[ft/second square]

+h = 10 ;//[ft]

+gc = 32.174 ;//[(ft*lbm)/(second square/lbf)]

+pe = (m*(g/gc)*h) ;//[ft*lbf]

+printf('Potential Energy  is equal to %i (ft)(lbf).\n',pe);
\ No newline at end of file
diff --git a/409/CH1/EX1.5/Example1_5.sce b/409/CH1/EX1.5/Example1_5.sce
new file mode 100755
index 000000000..2c7578093
--- /dev/null
+++ b/409/CH1/EX1.5/Example1_5.sce
@@ -0,0 +1,19 @@
+clear;

+clc;

+

+// Example 1.5

+printf('Example 1.5\n\n');

+//Page no.20

+// Solution

+

+// Basis 1 min

+// Assume 100lb means 100 lb mass 

+g = 10^6 ;//[ug mol]

+lb = 454 ;//[g mol]

+ml = .001 ;//[L]

+L = 3.531*10^(-2);//[ft^3]

+hr = 60 ;//[min]

+dy = 24 ;//[hr]

+pr_rate = (0.6*1*1*1*hr*dy/(g*lb*ml*L)); //[ft*lbf]

+

+printf('Production rate of glucose is %.4f lb mol/(cubic feet*day).\n',pr_rate);
\ No newline at end of file
diff --git a/409/CH1/EX1.6/Example1_6.sce b/409/CH1/EX1.6/Example1_6.sce
new file mode 100755
index 000000000..1669f2ea5
--- /dev/null
+++ b/409/CH1/EX1.6/Example1_6.sce
@@ -0,0 +1,18 @@
+clear;

+clc;

+

+// Example 1.6

+printf('Example 1.6\n\n');

+//Page no. 22

+// Solution

+

+// using suitable conversion factors inside front cover of book

+printf('By analysing dimensionally both sides of equation you can say that both values of 16.2 must have the units of microns(10^-6 m).\n');

+printf(' The exponential must be dimensionless so that 0.021 must have the associated units of s^(-1).\n');

+

+m = 39.27 ;//[inches]

+um = 10^(-6) ;//[meters]

+c1 = 16.2*m*um ;//[inches]

+mn = 60 ;//[seconds]

+c2 = 0.021*60;//[min^(-1)]

+printf('\n New modified expression so that we can put t in minutes and get d in inches is as follows,\n d(in) =  %.2e(1-e^(-%.2f*t(min))) \n',c1,c2);
\ No newline at end of file
diff --git a/409/CH1/EX1.7/Example1_7.sce b/409/CH1/EX1.7/Example1_7.sce
new file mode 100755
index 000000000..0f7862e64
--- /dev/null
+++ b/409/CH1/EX1.7/Example1_7.sce
@@ -0,0 +1,10 @@
+clear;

+clc;

+

+// Example 1.7

+printf('Example 1.7\n\n');

+// Page no. 23

+// Solution

+

+printf('By analysing dimensionally , both a and x have same units(from 1+(x^2/a^2)),thus left hand side of equation has units of 1/x(from d/dx),\nAnd right hand side has units of x^2 (from product a.x).\n');

+printf('\nTherefore something is wrong as the equation is not dimensionally consistent.\n');
\ No newline at end of file
diff --git a/409/CH1/EX1.8/Example1_8.sce b/409/CH1/EX1.8/Example1_8.sce
new file mode 100755
index 000000000..769ee17d8
--- /dev/null
+++ b/409/CH1/EX1.8/Example1_8.sce
@@ -0,0 +1,14 @@
+clear ;

+clc;

+

+// Example 1.8

+printf('Example 1.8\n\n');

+// Page no. 28

+// Solution

+

+// Using Scientifc notation

+x = 2.24 * 10^4 ; //[kg]

+y = 2.01 * 10^4 ;//[kg]

+D = x - y ;// Difference obtained by using scientific notation //[kg]

+

+printf(' Difference obtained by using scientific notation is %.4e kg.\n  Hence answer is good to 2 decimal places. \n',D);
\ No newline at end of file
diff --git a/409/CH1/EX1.9/Example1_9.sce b/409/CH1/EX1.9/Example1_9.sce
new file mode 100755
index 000000000..6065b257b
--- /dev/null
+++ b/409/CH1/EX1.9/Example1_9.sce
@@ -0,0 +1,12 @@
+clear;

+clc;

+

+// Example 1.9

+printf('Example 1.9\n\n');

+//Page no. 29

+// Solution

+

+um = 3 ;//[kb]

+kb = 1000 ;//[bp]

+bs_prs = (3*um*kb)/(1*1);

+printf('The number of base pairs are %i bp. \n',bs_prs);
\ No newline at end of file