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+clear;
+clc;
+
+// Example 1.5
+printf('Example 1.5\n\n');
+//Page no.20
+// Solution
+
+// Basis 1 min
+// Assume 100lb means 100 lb mass
+g = 10^6 ;//[ug mol]
+lb = 454 ;//[g mol]
+ml = .001 ;//[L]
+L = 3.531*10^(-2);//[ft^3]
+hr = 60 ;//[min]
+dy = 24 ;//[hr]
+pr_rate = (0.6*1*1*1*hr*dy/(g*lb*ml*L)); //[ft*lbf]
+
+printf('Production rate of glucose is %.4f lb mol/(cubic feet*day).\n',pr_rate); \ No newline at end of file