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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH3/EX3.10/Ex3_10.sce
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+//tension in the cable and reaction at a point
+//refer fig. 3.21 (a),(b)&(c)
+//Taking moment about A we get
+T=((25*12*cosd(30))+(10*6*cosd(30)))/(12*sind(15)) //kN
+//applying equilibrium conditions
+HA=T*cosd(15) //kN
+VA=10+25+T*sind(15) //kN
+RA=sqrt(HA^2+VA^2) //kN
+alpha=atand(VA/HA) //degree
+printf("tension T in cable BC is T=%.2f kN.\nRA=%.3f kN\nalpha=%.2f degree",T,RA,alpha)