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//tension in the cable and reaction at a point
//refer fig. 3.21 (a),(b)&(c)
//Taking moment about A we get
T=((25*12*cosd(30))+(10*6*cosd(30)))/(12*sind(15)) //kN
//applying equilibrium conditions
HA=T*cosd(15) //kN
VA=10+25+T*sind(15) //kN
RA=sqrt(HA^2+VA^2) //kN
alpha=atand(VA/HA) //degree
printf("tension T in cable BC is T=%.2f kN.\nRA=%.3f kN\nalpha=%.2f degree",T,RA,alpha)
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