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| author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
| commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
| tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3886/CH20/EX20.8 | |
| parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
| download | Scilab-TBC-Uploads-master.tar.gz Scilab-TBC-Uploads-master.tar.bz2 Scilab-TBC-Uploads-master.zip | |
Diffstat (limited to '3886/CH20/EX20.8')
| -rw-r--r-- | 3886/CH20/EX20.8/20_8.sce | 11 | ||||
| -rw-r--r-- | 3886/CH20/EX20.8/20_8.txt | 5 |
2 files changed, 16 insertions, 0 deletions
diff --git a/3886/CH20/EX20.8/20_8.sce b/3886/CH20/EX20.8/20_8.sce new file mode 100644 index 000000000..43c40ae5d --- /dev/null +++ b/3886/CH20/EX20.8/20_8.sce @@ -0,0 +1,11 @@ +//Pulley
+//refer fig. 20.6
+//Let a be the resulting acceleration and T be the tension in the rope
+//Angular acceleration of pulley
+//alpha=1.667*a rad/sec^2
+//Dynamic equilibrium condition for the block gives
+//T=(600-(600*a)/(9.81))
+//From kinetic equation for pulley
+T=(200*7.358)/(9.81) //N
+a=(600*9.81)/(800) //m/sec^2
+printf("\nT=%.3f N\na=%.3f m/sec^2",T,a)
diff --git a/3886/CH20/EX20.8/20_8.txt b/3886/CH20/EX20.8/20_8.txt new file mode 100644 index 000000000..8f083a423 --- /dev/null +++ b/3886/CH20/EX20.8/20_8.txt @@ -0,0 +1,5 @@ +
+--> exec('E:\My program EM\20. Rotation of rigid bodies\20.8.sce', -1)
+
+T=150.010 N
+a=7.357 m/sec^2
\ No newline at end of file |