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//Pulley
//refer fig. 20.6
//Let a be the resulting acceleration and T be the tension in the rope
//Angular acceleration of pulley
//alpha=1.667*a rad/sec^2
//Dynamic equilibrium condition for the block gives
//T=(600-(600*a)/(9.81))
//From kinetic equation for pulley
T=(200*7.358)/(9.81) //N
a=(600*9.81)/(800) //m/sec^2
printf("\nT=%.3f N\na=%.3f m/sec^2",T,a)
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