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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH2/EX2.30 | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3862/CH2/EX2.30')
-rw-r--r-- | 3862/CH2/EX2.30/Ex2_30.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3862/CH2/EX2.30/Ex2_30.sce b/3862/CH2/EX2.30/Ex2_30.sce new file mode 100644 index 000000000..9711396bc --- /dev/null +++ b/3862/CH2/EX2.30/Ex2_30.sce @@ -0,0 +1,22 @@ +clear +// + +// Two cylinders, A of weight 4000 N and B of weight 2000 N rest on smooth inclines. They are connected by a bar of negligible weight hinged to each cylinder at its geometric centre by smooth pins + +//variable declaration + +WA=4000.0 //weight of cylinder A,N +WB=2000.0 //weight of cylinder B,N + +thetaWA=60.0*%pi/180.0 //inclination of wall with cylinderA,° +thetaWB=45.0*%pi/180.0 //inclination of wall with cylinderB,° +thetaAb=15.0*%pi/180.0 //angle inclination bar with cylinder A ,N +thetaBb=15.0*%pi/180.0 //angle inclination bar with cylinder B ,N + +//he free body diagram of the two cylinders. Applying Lami’s theorem to the system of forces on cylinder A, we get + +C=WA*sin(thetaWA)/sin(thetaWA+(%pi/2)-thetaAb) + +//Consider cylinder B. Summation of the forces parallel to the inclined plane +P=(-WB*cos(thetaWB)+C*cos(thetaWA))/cos(thetaBb) +printf("\n P= %0.1f N",P) |