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+clear
+//
+
+// Two cylinders, A of weight 4000 N and B of weight 2000 N rest on smooth inclines. They are connected by a bar of negligible weight hinged to each cylinder at its geometric centre by smooth pins
+
+//variable declaration
+
+WA=4000.0 //weight of cylinder A,N
+WB=2000.0 //weight of cylinder B,N
+
+thetaWA=60.0*%pi/180.0 //inclination of wall with cylinderA,°
+thetaWB=45.0*%pi/180.0 //inclination of wall with cylinderB,°
+thetaAb=15.0*%pi/180.0 //angle inclination bar with cylinder A ,N
+thetaBb=15.0*%pi/180.0 //angle inclination bar with cylinder B ,N
+
+//he free body diagram of the two cylinders. Applying Lami’s theorem to the system of forces on cylinder A, we get
+
+C=WA*sin(thetaWA)/sin(thetaWA+(%pi/2)-thetaAb)
+
+//Consider cylinder B. Summation of the forces parallel to the inclined plane
+P=(-WB*cos(thetaWB)+C*cos(thetaWA))/cos(thetaBb)
+printf("\n P= %0.1f N",P)