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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH2/EX2.20/Ex2_20.sce | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3862/CH2/EX2.20/Ex2_20.sce')
-rw-r--r-- | 3862/CH2/EX2.20/Ex2_20.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/3862/CH2/EX2.20/Ex2_20.sce b/3862/CH2/EX2.20/Ex2_20.sce new file mode 100644 index 000000000..a6a5d8eb3 --- /dev/null +++ b/3862/CH2/EX2.20/Ex2_20.sce @@ -0,0 +1,18 @@ +clear +// + +//The body is in equilibrium under the action of applied force P, self-weight 1500 N and normal reaction R from the plane. Since R, which is normal to the plane, makes 30° with the vertical (or 60° with the horizontal), + +//variable declaration +W=1500.0 //weight of block,N +theta=30.0*%pi/180 //angle of inclination + +//sum of vertical Fy & sum of horizontal forces Fx is zero +//Assume direction of Fx is right +//Assume direction of Fy is up + +R=W/cos(theta) +printf("\n R= %0.2f N",R) + +P=R*sin(theta) +printf("\n P= %0.2f N",P) |