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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH2/EX2.20
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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+clear
+//
+
+//The body is in equilibrium under the action of applied force P, self-weight 1500 N and normal reaction R from the plane. Since R, which is normal to the plane, makes 30° with the vertical (or 60° with the horizontal),
+
+//variable declaration
+W=1500.0 //weight of block,N
+theta=30.0*%pi/180 //angle of inclination
+
+//sum of vertical Fy & sum of horizontal forces Fx is zero
+//Assume direction of Fx is right
+//Assume direction of Fy is up
+
+R=W/cos(theta)
+printf("\n R= %0.2f N",R)
+
+P=R*sin(theta)
+printf("\n P= %0.2f N",P)