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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 6_2
+clc;funcprot(0);
+// Given data
+D=1.00;// inch
+T=60.0;// °F
+p=80.0;// psig
+mdot=0.800;// lbm/s
+v=0.01603;// ft^3/lbm
+g_c=32.174;// lbm.ft/lbf.s^2
+g=32.174;// ft/s^2
+
+// Calculation
+V_in=(4*mdot*v)/(%pi*D^2*(1/12)^2);// ft/s
+p_in=94.7;// psia
+p_out=14.7;// psia
+V_out=[(V_in^2)+(2*g_c*v*(p_in-p_out)*144)]^(1/2);// ft/s
+Z_out=V_out^2/(2*g);// ft
+printf("\n(a)The outlet velocity from the nozzle,(V_out)_a=%3.0f ft/s \n(b)The height to which the stream of water rises above the nozzle outlet when the nozzle is pointed straight up,(Z_out)_b=%3.0f ft.",V_out,Z_out)