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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clear
+//Given
+//Given
+//We will divide this into two parts
+E_w = 10.0 //Gpa - Youngs modulus of wood
+E_s = 200.0 //Gpa - Youngs modulus of steel
+M = 30.0 //K.N-m _ applied bending moment
+n = E_s/E_w
+l_1 = 250 //mm
+l_2 = 10 //mm
+b_1 = 150.0 //mm
+b_2 = 150.0*n //mm
+A_1 = l_1* b_1 //mm2 - area of part_1
+y_1 = 125.0 //mm com distance from top
+A_2 =l_2*b_2 //mm2 - area of part_1
+y_2 = 255.0 //mm com distance from top
+y_net = (A_1*y_1 +A_2*y_2)/(A_1+A_2) //mm - The com of the whole system from top
+I_1 = b_1*(l_1**3)/12.0 + A_1*((y_1-y_net)**2) //Parallel axis theorm
+I_2 = b_2*(l_2**3)/12.0 + A_2*((y_2-y_net)**2)
+I_net = I_1 + I_2 //mm4 - the total moment of inertia
+c_s= y_net // The maximum distance in steel
+stress_steel = M*(10.0**6)*c_s/I_net //MPa - The maximum stress in steel
+
+c_w= l_1+l_2-y_net // The maximum distance in wood
+stress_wood = n*M*(10.0**6)*c_w/I_net //MPa - The maximum stress in wood
+
+printf("\n The maximum stress in steel %0.2f MPa",stress_steel)
+printf("\n The maximum stress in wood %0.2f MPa",stress_wood)