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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clear
+//Given
+//From example 5.8
+W = 4.0 //N/m - The force distribution
+L = 3 // m - The length of the force applied
+M = W*L/8.0 // KN.m The moment due to force distribution
+o = 30 // the angle of force applid to horizantal
+l = 150.0 //mm length of the crossection
+b = 100.0 //mm - width of the crossection
+//
+M_z = M*(cos(3.14/6))
+M_y = M*(sin(%pi/6))
+I_z = b*(l**3)/12.0
+I_y = l*(b**3)/12.0
+//tanb = I_z /I_y *tan30
+b = atand((I_z*tan(3.14/6.0)/I_y))
+printf("\n The angle at which neutral axis locates is %0.3f degrees",b)