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+// Problem no 4.4.9,Page No.99
+
+clc;clear;
+close;
+M_C=40 //KNM //Moment at Pt C
+w=20 //KNm //u.d.l on L_AD
+L=10 //m //Length of beam
+L_CB=5 //m //Length of CB
+L_DC=1 //m //Length of DC
+L_AD=4 //m //Length of AD
+
+//Calculations
+
+//Let R_A & R_B be the reactions at A & B
+//R_A+R_B=80
+
+//Taking Moment at A
+//M_A=0=R_B*L-M-w*L_AD**2*2**-1
+R_B=(w*L_AD**2*2**-1+M_C)*L**-1
+R_A=80-R_B
+
+//Shear Force Calculations
+
+//Shear Force at B
+V_B=R_B
+
+//Shear Force at C
+V_C=V_B
+
+//Shear Force at D
+V_D=V_C
+
+//Shear Force at A
+V_A=V_D-w*L_AD
+
+//Pt of contraflexure
+//Let E be the pt and BE=x
+//V_E=0=R_B-w*(L_BE-L_DC-L_CB)
+L_BE=R_B*w**-1+L_DC+L_CB;
+x=L_BE
+
+//Bending Moment Calculations
+
+//Bending Moment at B
+M_B=0
+
+//Bending Moment at C
+M_C1=R_B*L_CB
+M_C2=M_C1-M_C
+
+//Bending Moment at D
+M_D=R_B*(L_CB+L_DC)-M_C
+
+//Bending Moment at A
+M_A=R_B*L-M_C-w*L_AD**2*2**-1
+
+//Bending Moment at E
+L_ED=L_BE-(L_DC+L_CB)
+M_E=R_B*L_BE-M_C-w*L_ED**2*2**-1
+
+//Result
+printf("The Shear Force and Bending Moment Diagrams are the results")
+
+//Plotting the Shear Force Diagram
+subplot(2,1,1)
+X1=[0,L_CB,L_CB+L_DC,L_CB+L_DC+L_AD,L_CB+L_DC+L_AD]                   
+Y1=[V_B,V_C,V_D,V_A,0]
+Z1=[0,0,0,0,0]
+plot(X1,Y1,X1,Z1)
+xlabel("Length x in m")
+ylabel("Shear Force in kN")
+title("the Shear Force Diagram")
+
+//Plotting the Bending Moment Diagram
+subplot(2,1,2)
+X2=[0,L_CB,L_CB,L_CB+L_DC,L_CB+L_DC+L_ED,L_CB+L_DC+L_AD]
+Y2=[M_B,M_C1,M_C2,M_D,M_E,M_A]          
+Z2=[0,0,0,0,0,0]
+plot(X2,Y2,X2,Z2)
+xlabel("Length in m")
+ylabel("Bending Moment in kN.m")
+title("the Bending Moment Diagram")