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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3765/CH1/EX1.4/Ex1_4.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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diff --git a/3765/CH1/EX1.4/Ex1_4.sce b/3765/CH1/EX1.4/Ex1_4.sce new file mode 100644 index 000000000..775b45071 --- /dev/null +++ b/3765/CH1/EX1.4/Ex1_4.sce @@ -0,0 +1,24 @@ +clc +// Example 1.4.py +// For thre pressure vessel in Example 1.2, calculate the total internal +// energy of the gas stored in the vessel. + +// Variable declaration from example 1.2 +V = 10 // volume of vessel (m^3) +p = 20.0 // pressure (atm) +T = 300 // temperature (Kelvin) + +R = 287.0 // gas constant (J/Kg/K) +gamma1 = 1.4 // ratio of specific heats for air + +// Calculations +cv = R / (gamma1-1) // specific heat capacity at constant volume(J/Kg K) +e = cv * T // internal energy per Kg (J/Kg) +p = p * 101000.0 // units conversion to N/m^2 +rho = p/R/T // from ideal gas equation of state (Kg/m^3) +m = V * rho // total mass = volume * density (Kg) +E = m*e // total energy in J + +// Result +printf("\n Total internal energy is %.2e J", E) + |