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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clear//
+
+//Variables
+
+I1 = 0.5 * 10**-3 //Diode current1 (in Ampere)
+V1 = 340 * 10**-3 //Voltage1 (in volts)
+I2 = 15 * 10**-3 //Diode current2 (in Ampere)
+V2 = 440 * 10**-3 //Voltage2 (in volts)
+
+//Calculation
+
+n = 4/log(30) //By solving both the given equations
+
+//Result
+
+printf("\n Value of n is %0.2f .",n)