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clear//
//Variables
I1 = 0.5 * 10**-3 //Diode current1 (in Ampere)
V1 = 340 * 10**-3 //Voltage1 (in volts)
I2 = 15 * 10**-3 //Diode current2 (in Ampere)
V2 = 440 * 10**-3 //Voltage2 (in volts)
//Calculation
n = 4/log(30) //By solving both the given equations
//Result
printf("\n Value of n is %0.2f .",n)
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