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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Fluid System By Shiv Kumar
+//Chapter 6 - Kaplan and Propeller Turbines
+//Example 6.7
+//To Find (a)Diameter of Runner (b)Speed (c)Specific Speed
+
+clc
+clear
+
+//Given:
+ H=32; //Head, m
+ P=16000; //Shaft Power, KW
+ D_per=190; //Percentage by which Diameter of Runner(D)is Larger than diameter of Boss(d)
+ eta_0=91/100; //Overall Efficiency
+ Ku=2; //Speed Ratio
+ Kf=0.64; //Flow Ratio
+
+//Data Required:
+ rho=1000; //Density of Water, Kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations
+
+ Vfi=Kf*sqrt(2*g*H); //Velocity of Flow at Inlet, m/s
+ ui= Ku*sqrt(2*g*H); //Velocity of Runner at Inlet, m/s
+
+ Q=P*10^3/(rho*g*H*eta_0); //Discharge, m^3/s
+
+
+ d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*((D_per/100+1)^2-1))); // Diameter of Hub ,m
+ //(a) Diameter of Runner ,D
+ D=d+(D_per/100)*d; //m
+
+ //(b) Speed,N
+ N=ui*60/(%pi*D); // rpm
+//(iii) Specific Speed of Turbine, Ns
+ Ns=N*P^(1/2)/(H^(5/4)); // SI Units
+
+
+//Results
+ printf("(a)Diameter of Runner , D=%.3f m\n",D)
+ printf(" (b)Speed, N =%.2f rpm\n",N) //The answer vary due to round off error
+ printf(" (c)Specific Speed, Ns =%.2f (SI Units)\n",Ns) //The answer provided in the textbook is wrong.
+