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+//Fluid Systems - By - Shiv Kumar
+//Chapter 11 - Centrifugal Pumps
+//Example 11.26
+//To Calculate the Specific Speed of Pump and the Power Input and Find the Head, Discharge and Power required at 900 rpm.
+
+      clc
+      clear
+
+//Given Data:-
+        
+                N=1500;         //Speed, rpm
+                Q=0.2;            //Discharge, m^3/s
+                H=15;           //Head, m
+                eta_o=0.68;         //Overall Efficiency
+              N2=900;          //Speed, rpm
+ 
+ //Data Used:-
+        rho=1000;        //Density of water, kg/m^3
+         g=9.81;          //Acceleratio due to gravity, m/s^2
+
+
+//Computations:-
+          Ns=N*Q^(1/2)/(H^(3/4));        //Specific Speed of Pump, SI Units
+          P=rho*g*Q*H /eta_o;          //Power Input, W 
+
+         Q1=Q;     H1=H;        N1=N;      P1=P;
+          Q2=Q1*(N2/N1);        // m^3/s
+          H2=H1*(N2/N1)^2;       //m
+          P2=P1*(N2/N1)^3;       //W
+
+//Results:-
+        printf("Specific Speed of Pump, Ns=%.2f (SI Units)\n",Ns)
+        printf(" Power Input, P=%.2f W\n",P)
+        printf(" At 900 rpm (Condition 2)\n\t ")
+            printf(" Head, H2=%.1f m \n\t Discharge,  Q2=%.2f m^3/s,\n\t Power required, P2=%.2f W",H2,Q2,P2)
+
+