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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3750/CH4/EX4.1 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3750/CH4/EX4.1')
| -rw-r--r-- | 3750/CH4/EX4.1/Ex4_1.sce | 31 |
1 files changed, 31 insertions, 0 deletions
diff --git a/3750/CH4/EX4.1/Ex4_1.sce b/3750/CH4/EX4.1/Ex4_1.sce new file mode 100644 index 000000000..cdf00ec65 --- /dev/null +++ b/3750/CH4/EX4.1/Ex4_1.sce @@ -0,0 +1,31 @@ +//Strength Of Material By G.H.Ryder
+//Chapter 4
+//Example 1
+//To calculate the maximum pressure set up in the oil
+clc();
+
+//Initialization of Variables
+d=6; //diameter of plunger, Unit in mm
+Mp=1; //Mass of plunger, Unit in Kg
+m=1.5; //Mass dropped on the plunger, Unit in kg
+v=5000; // Volume of oil, Unit in cm^3
+K=2800; //Bulk Modulus, Unit in N/mm^2
+g=9.81; //acceleration due to gravity, Unit in m/sec^2
+h=5; //Height, Unit in cm
+
+//Computations
+
+// Let p be addtional momentary maximum stress set up by falling weight
+//Loss of PE=m*g*(h*10+P*v*10^3+4)/(%pi*d^2)Nmm.......(i)
+//Gain of Strain energy=(P^2/2K)*v*10^3 Nmm.......(ii)
+//Equating (i) and (ii) and multiplying by K/(v*10^3),we get quadratic equation in P with coefficients
+a=1/2;
+b=-m*g*4/(%pi*d^2);
+c=-m*g*h*10*K/(v*10^3);
+
+
+p=(-b+sqrt(b^2-4*c*a))/(2*a); //solution for quadratic equation in P , Unit in N/mm^2, The answer vary due to round off error
+Pmax=p+Mp*g*4/(%pi*d^2); //Maximum pressure ,Unit in N/mm^2, The answer vary due to round off error
+
+//Result
+printf("Final Maximum Pressure set up in oil is %.2f N/mm^2",Pmax)
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