From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3750/CH4/EX4.1/Ex4_1.sce | 31 +++++++++++++++++++++++++++++++
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+//Strength Of Material By G.H.Ryder
+//Chapter 4
+//Example 1
+//To calculate the maximum pressure set up in the oil
+clc();
+
+//Initialization of Variables
+d=6; //diameter of plunger, Unit in mm
+Mp=1;  //Mass of plunger, Unit in Kg
+m=1.5;  //Mass dropped on the plunger, Unit in kg
+v=5000;  // Volume of oil, Unit in cm^3
+K=2800;   //Bulk Modulus, Unit in N/mm^2
+g=9.81;   //acceleration due to gravity, Unit in m/sec^2
+h=5;    //Height, Unit in cm
+
+//Computations
+
+// Let p be addtional momentary maximum stress set up by falling weight
+//Loss of PE=m*g*(h*10+P*v*10^3+4)/(%pi*d^2)Nmm.......(i)
+//Gain of Strain energy=(P^2/2K)*v*10^3 Nmm.......(ii)
+//Equating (i) and (ii) and multiplying by K/(v*10^3),we get quadratic equation in P with coefficients
+a=1/2; 
+b=-m*g*4/(%pi*d^2);
+c=-m*g*h*10*K/(v*10^3);
+
+
+p=(-b+sqrt(b^2-4*c*a))/(2*a);   //solution for quadratic equation in P  , Unit in N/mm^2,        The answer vary due to round off error
+Pmax=p+Mp*g*4/(%pi*d^2);  //Maximum pressure ,Unit in N/mm^2,         The answer vary due to round off error
+
+//Result
+printf("Final Maximum Pressure set up in oil is %.2f N/mm^2",Pmax)
-- 
cgit