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+//Chapter 10:Traction Drives

+//Example 6

+clc;

+

+//Variable Initialization

+Ml=1000      //weight of the empty train in tonne

+Mt=5000      //weight of the fully loaded train in tonne

+G=15         //gradient of the track

+V=30         //maximum speed of the train 

+r=40         //train resistance in N/tonne

+u=0.25       //co-efficient of adhesion

+alpha=0.3    //acelaration in kmphps

+

+W=100            //weight of each locomotive

+

+//Solution

+Md=W//Md=W*n

+Fm=9810*u*Md

+//By expanding and clubbing similar terms we get

+//(G*9.81*Mt)+(9.81*W*n*G)-((r*Mt)+(r*W*n))

+//(G*9.81*Mt)-(r*Mt)+(9.81*W*n*G)-(r*W*n)

+Fb1=(9.81*Mt*G)-(r*Mt)          //By expanding we get 

+Fb2=(9.81*W*G)-(r*W)//By expanding we get Mt*r+W*n*r

+mprintf("\nFm=%d*n",Fm)

+mprintf("\nFb=%d*n+%d",Fb2,Fb1)

+mprintf("\nEquating Fb and Fm we get")

+n=535750/(245250-10715)

+if (n>2) then 

+    n=3

+end

+mprintf("\nThe number of locomotives is n:%d",n)

+Md=W*n

+M=Ml+W*n

+Ft=277.8*1.1*M*alpha+9.81*M*G+M*r  

+Fm=9810*0.3*Md

+if (Fm>Ft) then

+    mprintf("\nThe train can be accelarated with %d locomotives",n)

+end