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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 13_2
+clc;clear;
+// Given values
+b=0.8;// Width in m
+y=0.52;// Flow depth in m
+g=9.81;// m/s^2
+theta=60;// Trapezoid angle in degree
+alpha=0.3;// Bottom slope angle
+//Properties
+n=0.030;// The Manning coefficient for an open channel with weedy surfaces
+
+//Calculation
+A_c=(y*(b+(y/tand(theta))));//The cross-sectional area in m^2
+p=b+((2*y)/sind(theta));// Perimeter in m
+R_h=A_c/p;// Hydraulic radius of the channel
+S_0=tand(alpha);//The bottom slope of the channel
+a=1;// m^(1/3)/s
+v=(a/n)*(A_c*R_h^(2/3)*S_0^(1/2));// The flow rate through the channel in m^3/s
+printf('The flow rate through the channel is determined from the Manning equation to be,v=%0.2f m^3/s\n',v);
+//The flow rate for a bottom angle of 1° can be determined by using S_0= tan alpha=tan 1°
+alpha_1=1;// degree
+S_01=tand(alpha_1);// The bottom slope of the channel
+v=(a/n)*(A_c*R_h^(2/3)*S_01^(1/2));// The flow rate through the channel in m^3/s
+printf('The flow rate for a bottom angle of 1°,v=%0.1f m^3/s\n',v);