diff options
| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /371/CH16/EX16.9 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '371/CH16/EX16.9')
| -rwxr-xr-x | 371/CH16/EX16.9/16_9.sci | 5 |
1 files changed, 5 insertions, 0 deletions
diff --git a/371/CH16/EX16.9/16_9.sci b/371/CH16/EX16.9/16_9.sci new file mode 100755 index 000000000..d9d89d492 --- /dev/null +++ b/371/CH16/EX16.9/16_9.sci @@ -0,0 +1,5 @@ +//Faults and Protection// +//Example 16.9// +printf(' Thus from the table we see at a value of circuit inductance 1.592mH,I^2t value of breaker is 4.9*10^5A^2s and selectivity between fuse and breakeris I^2tFuse/I^2t Breaker=4*10^5/4.97*10^5=1.01'); +printf('\nAs this is just the border case we will go for the next value of inductancei.e,1.91mH.where selectivity=5*10^5/4.34*10^5=1.18'); +printf('\nThus the additional inductance required is=1.91-1.273=0.637mH');
\ No newline at end of file |