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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clc
+V1 = 0.3 // Initial volume in m^3
+V2 = 0.15 // Final volume in m^3
+P = 0.105 // Initial Pressure in MPa
+Q = -37.6 // Heat transferred in kJ
+W = P*(V2-V1)*1e6 // Work done
+U = Q*1e3-W // Internal energy change
+printf("\n Example 4.1")
+printf("\n The internal energy of the gas decrease by %f kJ in the process.",abs(U)/1e3)
+