initial commit / add all books

10 files changed, 144 insertions, 0 deletions

diff --git a/3685/CH4/EX4.1/Ex4_1.sce b/3685/CH4/EX4.1/Ex4_1.sce
new file mode 100644
index 000000000..f60211655
--- /dev/null
+++ b/3685/CH4/EX4.1/Ex4_1.sce
@@ -0,0 +1,10 @@
+clc

+V1 = 0.3 // Initial volume in m^3

+V2 = 0.15 // Final volume in m^3

+P = 0.105 // Initial Pressure in MPa

+Q = -37.6 // Heat transferred in kJ

+W = P*(V2-V1)*1e6 // Work done

+U = Q*1e3-W // Internal energy change

+printf("\n Example 4.1")

+printf("\n The internal energy of the gas decrease by %f kJ in the process.",abs(U)/1e3)

+

diff --git a/3685/CH4/EX4.1/Ex4_1.txt b/3685/CH4/EX4.1/Ex4_1.txt
new file mode 100644
index 000000000..128460bec
--- /dev/null
+++ b/3685/CH4/EX4.1/Ex4_1.txt
@@ -0,0 +1,3 @@
+

+ Example 4.1

+ The internal energy of the gas decrease by 21.850000 kJ in the process. 
\ No newline at end of file
diff --git a/3685/CH4/EX4.2/Ex4_2.sce b/3685/CH4/EX4.2/Ex4_2.sce
new file mode 100644
index 000000000..6fdbe4dc3
--- /dev/null
+++ b/3685/CH4/EX4.2/Ex4_2.sce
@@ -0,0 +1,26 @@
+clc

+Qacb = 84 // Heat transfer along the path acb in kJ 

+Wacb = 32 // Work done along the path acb in kJ

+Uba = Qacb-Wacb // Ub-Ua

+// Part (a)

+Wadb = 10.5 // Work done along the path adb in kJ

+Qadb = Uba+Wadb // Heat flow into the system along the path adb

+printf("\n Example 4.2")

+printf("\n The heat flow into the system along the path adb is %f kJ.",Qadb)

+

+

+// Part (b)

+Wb_a = -21 // work done along the path ba in kJ

+Uab = - Uba // Change in internal energy along the path ab in kJ

+Qb_a = Uab+Wb_a // Heat liberated along the path b-a

+printf("\n The heat liberated along the path b-a is %d kJ.",Qb_a)

+

+// Part (c)

+Wdb = 0 // Constant volume

+Wad = 10.5 // work done along the path ad in kJ

+Wadb = Wdb-Wad // work done along the path adb in kJ

+Ud = 42

+Ua = 0

+Qad = Ud-Ua+Wad // Heat flow into the system along the path ad in kJ

+Qdb = Qadb-Qad  //Heat flow into the system along the path db in kJ

+printf("\n The heat absorbed in the path ad and db are %f kJ nd %d kJ respectively.",Qad,Qdb)

diff --git a/3685/CH4/EX4.2/Ex4_2.txt b/3685/CH4/EX4.2/Ex4_2.txt
new file mode 100644
index 000000000..097f199f9
--- /dev/null
+++ b/3685/CH4/EX4.2/Ex4_2.txt
@@ -0,0 +1,5 @@
+ 

+ Example 4.2

+ The heat flow into the system along the path adb is 62.500000 kJ.

+ The heat liberated along the path b-a is -73 kJ.

+ The heat absorbed in the path ad and db are 52.500000 kJ nd 10 kJ respectively.
\ No newline at end of file
diff --git a/3685/CH4/EX4.3/Ex4_3.sce b/3685/CH4/EX4.3/Ex4_3.sce
new file mode 100644
index 000000000..47445d284
--- /dev/null
+++ b/3685/CH4/EX4.3/Ex4_3.sce
@@ -0,0 +1,25 @@
+clc

+// Process a-b

+Qab = 0 // Heat transfer along the path ab in kJ/ min

+Wab = 2170 // Work transfer along the path ab in kJ/min

+Eab = Qab-Wab // Change in internal energy along the path ab in kJ/min

+// Process b-c

+Qbc = 21000 // Heat transfer along the path bc in kJ/ min

+Wbc = 0 // Work transfer along the path bc in kJ/min

+Ebc = Qbc-Wbc // Change in internal energy along the path bc in kJ/min

+// Process c-d

+Qcd = -2100 // Heat transfer along the path cd in kJ/ min

+Ecd = -36600  // Change in internal energy along the path cd in kJ/min

+Wcd = Qcd-Ecd  // Work transfer along the path cd in kJ/min

+// Process d-a

+Q = -17000  // Total heat transfer in kJ/min

+Qda = Q-Qab-Qbc-Qcd // Heat transfer along the path da in kJ/ min 

+Eda = -Eab-Ebc-Ecd  // Change in internal energy along the path da in kJ/min 

+Wda = Qda-Eda // Work transfer along the path da in kJ/min

+printf("\n Example 4.3")

+

+M = [Qab Wab Eab ; Qbc Wbc Ebc; Qcd Wcd Ecd; Qda Wda Eda];

+disp(M,"The completed table is:")

+W = Qab+Qbc+Qcd+Qda

+printf("\n Net rate of work output is %f kW",W/60)

+

diff --git a/3685/CH4/EX4.3/Ex4_3.txt b/3685/CH4/EX4.3/Ex4_3.txt
new file mode 100644
index 000000000..12bd3b410
--- /dev/null
+++ b/3685/CH4/EX4.3/Ex4_3.txt
@@ -0,0 +1,9 @@
+  Example 4.3 

+ The completed table is:   

+ 

+    0.        2170.   - 2170.   

+    21000.    0.        21000.  

+  - 2100.     34500.  - 36600.  

+  - 35900.  - 53670.    17770.  

+

+ Net rate of work output is -283.333333 kW .
\ No newline at end of file
diff --git a/3685/CH4/EX4.4/Ex4_4.sce b/3685/CH4/EX4.4/Ex4_4.sce
new file mode 100644
index 000000000..e1e737767
--- /dev/null
+++ b/3685/CH4/EX4.4/Ex4_4.sce
@@ -0,0 +1,29 @@
+clc

+// Part (a)

+m = 3 // mass of substance in kg

+V1 = 0.22 // Initial volume of system in m^3

+P1 = 500 // Initial pressure of system in kPa 

+P2 = 100 // Final pressure of system in kPa  

+V2 = V1*(P1/P2)^(1/1.2) // Final volume of system

+dU = 3.56*(P2*V2-P1*V1) // Change in internal energy of substance in kJ/kg

+n = 1.2 // polytropic index

+W = (P2*V2-P1*V1)/(1-n) // work done in process

+Q = dU+W // Heat addition in process

+

+printf("\n Example 4.4")

+printf("\n Part A:")

+printf("\n For the quasi static process is: \n ")

+printf("Q:   %fkJ",Q)

+printf("\n dU: %fkJ",dU)

+printf("\n W: %fkJ",W)

+//The provided in the textbook is wrong

+// Part (b)

+printf("\n\n Part B:")

+Qb = 30 // heat transfer in kJ 

+Wb = Qb-dU // Work done in kJ

+printf("\n Work transfer for the process is %fkJ.",Wb) 

+//The answers vary due to round off error

+// Part (c)

+printf("\n\n Part C:")

+printf("\n Wb is not equal to integral(p*dv) since the process is not quasi static.")

+

diff --git a/3685/CH4/EX4.4/Ex4_4.txt b/3685/CH4/EX4.4/Ex4_4.txt
new file mode 100644
index 000000000..99a4d2cd4
--- /dev/null
+++ b/3685/CH4/EX4.4/Ex4_4.txt
@@ -0,0 +1,13 @@
+ 

+ Example 4.4

+ Part A:

+ For the quasi static process is: 

+ Q:   37.267641kJ

+ dU: -92.133889kJ

+ W: 129.401530kJ

+

+ Part B:

+ Work transfer for the process is 122.133889kJ.

+

+ Part C:

+ Wb is not equal to integral(p*dv) since the process is not quasi static. 
\ No newline at end of file
diff --git a/3685/CH4/EX4.5/Ex4_5.sce b/3685/CH4/EX4.5/Ex4_5.sce
new file mode 100644
index 000000000..70775eda9
--- /dev/null
+++ b/3685/CH4/EX4.5/Ex4_5.sce
@@ -0,0 +1,21 @@
+clc

+V1 = 0.03 // initial volume in m^3

+P1 = 170 // Initial pressure in kPa

+P2 = 400 // Final pressure in kPa

+V2 = 0.06 // Final volume in m^3

+U = 3.15*(P2*V2-P1*V1) // internal energy in kJ

+B = [P1 P2]' 

+A = [1 V1 ; 1 V2] 

+x = inv(A)*B 

+a = x(1) ; b = x(2) 

+function P=pressure(V) 

+  P = a+b*V 

+endfunction 

+W = intg(V1,V2,pressure)  

+Q = U+W // heat flow into the system in kJ

+

+printf("\n Example 4.5")

+printf("\n The work done by the system is %f kJ",W)

+printf("\n The heat flow into the system is %f kJ",Q)

+

+

diff --git a/3685/CH4/EX4.5/Ex4_5.txt b/3685/CH4/EX4.5/Ex4_5.txt
new file mode 100644
index 000000000..aad10523c
--- /dev/null
+++ b/3685/CH4/EX4.5/Ex4_5.txt
@@ -0,0 +1,3 @@
+ Example 4.5

+ The work done by the system is 8.550000 kJ

+ The heat flow into the system is 68.085000 kJ
\ No newline at end of file