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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 2.1
+
+clc;
+clear;
+
+// Given data
+
+// An amplifier( Refer Fig. 2.5(a) )
+Acl = -10; // Closed loop gain
+Ri = 10 * 10^3; // Input resistance of amplifier(Ω)
+
+// Solution
+
+// Since it is mentioned to design an amplifier, it means to calculate values for Rf(Feedback resistance) and R1.
+disp("Referring Fig. 2.5(a), we choose R1 as 10 kΩ i.e equal to input resistance of amplifier.");
+R1 = Ri;
+// Acl = -1 * Rf/R1;
+// Therefore;
+Rf= - Acl * Ri;
+printf(' The calculated value of Rf(Feedback resistane) is Rf = %d kΩ. \n',Rf/1000);