From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3682/CH2/EX2.1/Ex2_1.sce | 20 ++++++++++++++++++++
 1 file changed, 20 insertions(+)
 create mode 100644 3682/CH2/EX2.1/Ex2_1.sce

(limited to '3682/CH2/EX2.1/Ex2_1.sce')

diff --git a/3682/CH2/EX2.1/Ex2_1.sce b/3682/CH2/EX2.1/Ex2_1.sce
new file mode 100644
index 000000000..9e450dd8e
--- /dev/null
+++ b/3682/CH2/EX2.1/Ex2_1.sce
@@ -0,0 +1,20 @@
+// Exa 2.1
+
+clc;
+clear;
+
+// Given data
+
+// An amplifier( Refer Fig. 2.5(a) )
+Acl = -10; // Closed loop gain
+Ri = 10 * 10^3; // Input resistance of amplifier(Ω)
+
+// Solution
+
+// Since it is mentioned to design an amplifier, it means to calculate values for Rf(Feedback resistance) and R1.
+disp("Referring Fig. 2.5(a),  we choose R1 as 10 kΩ i.e equal to input resistance of amplifier.");
+R1 = Ri;
+// Acl = -1 * Rf/R1;
+// Therefore;
+Rf= - Acl * Ri;
+printf(' The calculated value of Rf(Feedback resistane) is Rf = %d kΩ. \n',Rf/1000);
-- 
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