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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 11.2
+// Computation of (a) Shunt field current (b) Armature current (c) Developed
+// torque (d) Armature current if a resistor inserted in series with the shunt
+// field circuit caused the speed to increase to 900 r/min (e) External
+// resistance required in series with the shunt field circuit to operate
+// at 900 r/min
+// Page No. 450
+
+clc;
+clear;
+close;
+
+// Given data
+HP=125;
+perratedload=0.854; // Percentage rated load
+VT=240; // Voltage value of motor
+RF=49.2; // Resistance of shunt motor
+Nf=577; // Turns per pole of the shunt motor
+Ns=4.5;
+Ra=0.0172; // Armature resistance
+RIP=0.005; // Interpole winding resistance
+Rs=0.0023; // Resistance of series field winding
+n1=850; // Speed of shunt motor
+n2=900;
+F2=4000;
+
+// (a) Shunt field current
+
+IF=VT/RF; // Field current
+
+// (b) Armature current
+Pin=HP*746/perratedload; // Input power
+IT=Pin/VT; // Total current
+Ia1=IT-IF;
+
+// (c) Developed torque
+
+Racir=Ra+RIP+Rs;
+Ea=VT-Ia1*Racir; // Armature emf
+Pmech=Ea*Ia1; // Mechanical power
+TD=Pmech*5252/n1/746; // Torque developed
+
+// (d) Armature current if a resistor inserted in series with the shunt field
+// circuit caused the speed to increase to 900 r/min
+
+Ia2=Ia1*n2/n1;
+
+//(e) External resistance required in series with the shunt field circuit to
+// operate at 900 r/min
+IF2=(F2-0.90*Ns*Ia2)/Nf;
+Rx=(VT/IF2)-RF;
+
+
+// Display result on command window
+printf("\n Shunt field current = %0.2f A ",IF);
+printf("\n Armature current = %0.2f A ",Ia1);
+printf("\n Developed torque = %0.1f lb-ft ",TD);
+printf("\n Armature current if a resistor inserted in series = %0.0f A ",Ia2);
+printf("\n External resistance required = %0.1f Ohm ",Rx);
+
+