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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 6.7//
+
+//From hooke law'
+s=0.2489;//nm //nanometer // modulus of elasticity
+s1=0.2480;// nm //nanometer // modulus of elasticity
+e=(s-s1)/s1
+printf("e = %f ",e)
+s2=1000;//Mpa //MegaPascal //sigma
+E=s2/e
+mprintf("\n E = %e",E)
+mprintf(" 275 GPa (As G=10^9) (Answer calculated in the textbook is wrong)")