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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 6.10//
+
+ap=5*10^-1;//percent per hour
+Q=2*10^5;//J/mol //activation energy
+R=8.314;//J/mol.K// universal gas constant
+T=1273;//K //Kelvin //absolute temperature
+T1=873;//given //absolute temperature
+C=ap*%e^((Q)/(R*T))
+mprintf("C = %e percent per hour",C)
+//applying this amount to the service temprature yield
+C1=C*%e^-((Q)/(R*T1))
+mprintf("\n C1 = %e percent per hour",C1)