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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3557/CH18/EX18.6/Ex18_6.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3557/CH18/EX18.6/Ex18_6.sce')
-rw-r--r-- | 3557/CH18/EX18.6/Ex18_6.sce | 9 |
1 files changed, 9 insertions, 0 deletions
diff --git a/3557/CH18/EX18.6/Ex18_6.sce b/3557/CH18/EX18.6/Ex18_6.sce new file mode 100644 index 000000000..23cd0d564 --- /dev/null +++ b/3557/CH18/EX18.6/Ex18_6.sce @@ -0,0 +1,9 @@ +//Example18.6//
+
+a=8.9*10^4;//(amperes/m)(webers/m^2) // Area
+mprintf("a= %e (amperes.webers)/m^3",a)
+//one ampere weber is equal to 1joule. The area is then a volume density of energy ,or
+e=8.9*10^4//J/m^3 //energy loss
+b= 10^-3; //As 1Kilogram = 10^3 gram
+e1=e*b
+mprintf("\ne1 = %i kJ/m^3 (per cycle) (As 1Kilogram = 10^3 garm)",e1)
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