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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 17.4//
+
+//For 100g of doped silicon there will be
+b=100;//ppb //Al by weight
+c=10^9;//given
+d=100;//g Al
+a=(b/c)*d
+mprintf("a = %e g Al",a)
+e=26.98;//g/g.atom //atomic mass of aluminium
+Al=a/e
+mprintf("\nAl = %e g atom",Al)
+f=28.09;//g/g.atom // atomic mass of Silicon
+Si=(b-a)/f
+mprintf("\nSi = %f g atoms",Si)
+pAl=((Al)/(Si+Al))*100
+mprintf("\npAl = %e atomic percent",pAl)