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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 15.4
+
+clc;
+clear all;
+
+// Given data
+// Second order filter
+
+R=47*10^3; // Ohms(R2=R3=R)
+C=0.0022*10^-6; // farads(C2=C3=C)
+
+// Solution
+
+Fl=1/(2*%pi*R*C); //low cutoff frequency(Hz)
+printf(' The low cutoff frequency for a high pass filter =%.2f kHz\n',Fl/1000);
+