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// Exa 15.4
clc;
clear all;
// Given data
// Second order filter
R=47*10^3; // Ohms(R2=R3=R)
C=0.0022*10^-6; // farads(C2=C3=C)
// Solution
Fl=1/(2*%pi*R*C); //low cutoff frequency(Hz)
printf(' The low cutoff frequency for a high pass filter =%.2f kHz\n',Fl/1000);
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