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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 4.6.1\n')
+//given data
+mprintf('NOTE:The mass given in textbook should be equal\n to 3.7 kgs and not 8.7 Kgs')
+m=3.7//mass in kg
+g=9.81// gravity
+K=7550////stiffness of in N/m
+u=0.22//coefficient of friction
+Fo=19.6//amp of force in N
+f=5//frequency of force
+//calculations
+F=u*m*g//frictional force
+W=2*%pi*f
+Wn=sqrt(K/m)
+bet=(W/Wn)
+X=(Fo/K)*sqrt(1-(4*F/(%pi*Fo))^2)/(1-bet^2)//Eqn 4.6.2 in Sec 4.6
+Ceq=4*F/(%pi*W*X)//equivalent viscous damping Eqn 4.6.1 in Sec 4.6
+//output
+mprintf('\nThe amplitude of vibration of mass is %f m\n The equivalent viscous damping is %f N-sec/m',X,Ceq)
+mprintf('\nNOTE: slight differnce in answer compared to textbook\n is due approximation of value of pi in the taxtbook')