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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 4.2.2\n')
+//given data
+Wd=9.8*2*%pi// damped natural freqency in rad/sec
+Wp=9.6*2*%pi//freqency from forced vibration test in rad/sec
+//calculations
+//(Wp/Wn)=sqrt(1-2*zeta^2)...(1) from Eqn 4.2.18 from Sec 4.2.1
+//(Wd/Wn)=sqrt(1-zeta^2)...(2) from Eqn 4.2.19 from Sec 4.2.1
+//dividing (1) by (2)
+x=(Wp/Wd)
+//x=[sqrt(1-2*zeta^2)]/[sqrt(1-zeta^2)]
+zeta=sqrt((1-x)/(2-x))//damping factor obtained on simplifying the above eqn
+//substituting for zeta in eqn 2 above
+Wn=Wd/sqrt(1-zeta^2)//natural frequency of system in rad/sec
+fn=Wn/(2*%pi)//natural frequency of system in Hz
+//output
+mprintf('The damping factor for the system is %f and\n the natural frequency is %4.4f rad/sec or %4.2f Hz',zeta,Wn,fn)
+mprintf('\nNOTE:The damping factor zeta given in textbook is 0.196,which is wrong.')