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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+mprintf('Mechanical vibrations by G.K.Grover\n Example 4.10.2\n')
+//given data
+m=75//mass of machine in kg
+K=11.76*10^5//stiffness of springs in N/m
+zeta=0.2
+mo=2//mass of piston in kg
+stroke=0.08//in m
+e=stroke/2//in m
+N=3000//spee in c.p.m
+//calculations
+Wn=sqrt(K/m)
+W=2*%pi*N/60
+bet=(W/Wn)
+y=(mo/m)
+Fo=mo*W^2*e//max force exerted
+X=y*e*bet^2/(sqrt((1-bet^2)^2+(2*zeta*bet)^2))//Eqn 4.3.2
+Ftr=Fo*sqrt(1+(2*zeta*bet)^2)/sqrt((1-bet^2)^2+(2*zeta*bet)^2)//force transmitted,Eqn 4.10.2 in Sec 4.10.1
+mprintf(' a)The amplitude of vibration of machine is %f m and the \n the vibratory force Ftr transmitted to the foundation is %5.4f N',X,Ftr)
+mprintf('\nNOTE: slight differnce in answer compared to textbook\n is due approximation of values in textbook')