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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH46/EX46.5/Example46_5.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/3472/CH46/EX46.5/Example46_5.sce b/3472/CH46/EX46.5/Example46_5.sce new file mode 100644 index 000000000..fecc3fbf5 --- /dev/null +++ b/3472/CH46/EX46.5/Example46_5.sce @@ -0,0 +1,29 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART IV : UTILIZATION AND TRACTION
+// CHAPTER 8: BRAKING
+
+// EXAMPLE : 8.5 :
+// Page number 811-812
+clear ; clc ; close ; // Clear the work space and console
+funcprot(0)
+
+// Given data
+area = 16.13 // Area of brakes(sq.cm/pole face)
+phi = 2.5*10**-3 // Flux(Wb)
+u = 0.2 // Co-efficient of friction
+W = 10.0 // Weight of car(tonnes)
+
+// Calculations
+a = area*10**-4 // Area of brakes(sq.m/pole face)
+F = phi**2/(2*%pi*10**-7*a) // Force(N)
+force = F*u // Braking effect considering flux and coefficient of friction(N)
+beta = u*F/(W*1000)*100 // Rate of retardation produced by braking effect(cm/sec^2)
+
+// Results
+disp("PART IV - EXAMPLE : 8.5 : SOLUTION :-")
+printf("\nBraking effect, F = %.f N", force)
+printf("\nRate of retardation produced by this braking effect, β = %.2f cm/sec^2", beta)
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