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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART IV : UTILIZATION AND TRACTION
+// CHAPTER 4: ILLUMINATION
+
+// EXAMPLE : 4.9 :
+// Page number 758-759
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+b = 27.45 // Breadth of hall(m)
+l = 45.75 // Length of hall(m)
+I_avg = 108.0 // Average illumination(lumens/sq.m)
+h = 0.75 // Height(m)
+cou = 0.35 // Co-efficient of utilization
+pf = 0.9 // Pereciation factor
+P_fl = 80.0 // Fluorescent lamp power(W)
+n_100 = 13.4 // Luminous efficiency for 100W filament lamp(lumens/watt)
+n_200 = 14.4 // Luminous efficiency for 200W filament lamp(lumens/watt)
+n_80 = 30.0 // Luminous efficiency for 80W fluorescent lamp(lumens/watt)
+
+// Calculations
+area = b*l // Area to be illuminated(Sq.m)
+I_total = area*I_avg // Total illumination on working plane(lumens)
+gross_lumen = I_total/(cou*pf) // Gross lumens required
+P_required = gross_lumen/n_200 // Power required for illumination(W)
+P_required_kW = P_required/1000 // Power required for illumination(kW)
+no_lamp = P_required/200 // Number of lamps
+P_required_new = gross_lumen/n_80 // Power required when fluorescent lamp used(W)
+P_required_new_kW = P_required_new/1000 // Power required when fluorescent lamp used(kW)
+P_saving = P_required_kW-P_required_new_kW // Saving in power(kW)
+
+// Results
+disp("PART IV - EXAMPLE : 4.9 : SOLUTION :-")
+printf("\nSuitable scheme: Whole area divided into %.f rectangles & 200-watt fitting is suspended at centre of each rectangle", no_lamp)
+printf("\nSaving in power consumption = %.1f kW", P_saving)