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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART IV : UTILIZATION AND TRACTION
+// CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS
+
+// EXAMPLE : 1.6 :
+// Page number 682
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+hp = 10.0 // IM rating(hp)
+V = 400.0 // IM voltage(V)
+pf = 0.8 // Lagging power factor
+n = 0.9 // Efficiency of IM
+I_sc = 7.2 // Short-circuit current at 160V(A)
+V_sc = 160.0 // Voltage at short-circuit(V)
+
+// Calculations
+I_fl = hp*746/(3**0.5*V*pf*n) // Full-load line current(A)
+I_sc_fv = V/V_sc*I_sc // Short-circuit current at full voltage(A)
+I_s = I_sc_fv/3.0 // Starting current with star-delta starter(A)
+I_s_fl = I_s/I_fl // Ratio of starting current to full load current
+
+// Results
+disp("PART IV - EXAMPLE : 1.6 : SOLUTION :-")
+printf("\nRatio of starting current to full-load current, I_s/I_fl = %.1f \n", I_s_fl)
+printf("\nNOTE: ERROR: Calculation mistake in final answer in textbook solution")