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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART IV : UTILIZATION AND TRACTION
// CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS
// EXAMPLE : 1.6 :
// Page number 682
clear ; clc ; close ; // Clear the work space and console
// Given data
hp = 10.0 // IM rating(hp)
V = 400.0 // IM voltage(V)
pf = 0.8 // Lagging power factor
n = 0.9 // Efficiency of IM
I_sc = 7.2 // Short-circuit current at 160V(A)
V_sc = 160.0 // Voltage at short-circuit(V)
// Calculations
I_fl = hp*746/(3**0.5*V*pf*n) // Full-load line current(A)
I_sc_fv = V/V_sc*I_sc // Short-circuit current at full voltage(A)
I_s = I_sc_fv/3.0 // Starting current with star-delta starter(A)
I_s_fl = I_s/I_fl // Ratio of starting current to full load current
// Results
disp("PART IV - EXAMPLE : 1.6 : SOLUTION :-")
printf("\nRatio of starting current to full-load current, I_s/I_fl = %.1f \n", I_s_fl)
printf("\nNOTE: ERROR: Calculation mistake in final answer in textbook solution")
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