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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH2 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '3472/CH2')
| -rw-r--r-- | 3472/CH2/EX2.1/Example2_1.sce | 31 | ||||
| -rw-r--r-- | 3472/CH2/EX2.2/Example2_2.sce | 32 | ||||
| -rw-r--r-- | 3472/CH2/EX2.3/Example2_3.sce | 39 |
3 files changed, 102 insertions, 0 deletions
diff --git a/3472/CH2/EX2.1/Example2_1.sce b/3472/CH2/EX2.1/Example2_1.sce new file mode 100644 index 000000000..641f5335a --- /dev/null +++ b/3472/CH2/EX2.1/Example2_1.sce @@ -0,0 +1,31 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.1 :
+// Page number 25-26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+M = 15000.0+10.0 // Water evaporated(kg)
+C = 5000.0+5.0 // Coal consumption(kg)
+time = 8.0 // Generation shift time(hours)
+
+//Calculations
+//Case(a)
+M1 = M-15000.0
+C1 = C-5000.0
+M_C = M1/C1 // Limiting value of water evaporation(kg)
+//Case(b)
+kWh = 0 // Station output at no load
+consumption_noload = 5000+5*kWh // Coal consumption at no load(kg)
+consumption_noload_hr = consumption_noload/time // Coal consumption per hour(kg)
+
+//Results
+disp("PART I - EXAMPLE : 2.1 : SOLUTION :-")
+printf("\nCase(a): Limiting value of water evaporation per kg of coal consumed, M/C = %.f kg", M_C)
+printf("\nCase(b): Coal per hour for running station at no load = %.f kg\n", consumption_noload_hr)
diff --git a/3472/CH2/EX2.2/Example2_2.sce b/3472/CH2/EX2.2/Example2_2.sce new file mode 100644 index 000000000..18ba2b484 --- /dev/null +++ b/3472/CH2/EX2.2/Example2_2.sce @@ -0,0 +1,32 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.2 :
+// Page number 26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+amount = 25.0*10**5 // Amount spent in 1 year(Rs)
+value_heat = 5000.0 // Heating value(kcal/kg)
+cost = 500.0 // Cost of coal per ton(Rs)
+n_ther = 0.35 // Thermal efficiency
+n_elec = 0.9 // Electrical efficiency
+
+//Calculations
+n = n_ther*n_elec // Overall efficiency
+consumption = amount/cost*1000 // Coal consumption in 1 year(kg)
+combustion = consumption*value_heat // Heat of combustion(kcal)
+output = n*combustion // Heat output(kcal)
+unit_gen = output/860.0 // Annual heat generated(kWh). 1 kWh = 860 kcal
+hours_year = 365*24.0 // Total time in a year(hour)
+load_average = unit_gen/hours_year // Average load on the power plant(kW)
+
+//Result
+disp("PART I - EXAMPLE : 2.2 : SOLUTION :-")
+printf("\nAverage load on power plant = %.2f kW\n", load_average)
+printf("\nNOTE: ERROR: Calculation mistake in the final answer in the textbook")
diff --git a/3472/CH2/EX2.3/Example2_3.sce b/3472/CH2/EX2.3/Example2_3.sce new file mode 100644 index 000000000..cd9d92df9 --- /dev/null +++ b/3472/CH2/EX2.3/Example2_3.sce @@ -0,0 +1,39 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.3 :
+// Page number 26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+consumption = 0.5 // Coal consumption per kWh output(kg)
+cal_value = 5000.0 // Calorific value(kcal/kg)
+n_boiler = 0.8 // Boiler efficiency
+n_elec = 0.9 // Electrical efficiency
+
+//Calculations
+input_heat = consumption*cal_value // Heat input(kcal)
+input_elec = input_heat/860.0 // Equivalent electrical energy(kWh). 1 kWh = 860 kcal
+loss_boiler = input_elec*(1-n_boiler) // Boiler loss(kWh)
+input_steam = input_elec-loss_boiler // Heat input to steam(kWh)
+input_alter = 1/n_elec // Alternator input(kWh)
+loss_alter = input_alter*(1-n_elec) // Alternate loss(kWh)
+loss_turbine = input_steam-input_alter // Loss in turbine(kWh)
+loss_total = loss_boiler+loss_alter+loss_turbine // Total loss(kWh)
+output = 1.0 // Output(kWh)
+Input = output+loss_total // Input(kWh)
+
+//Results
+disp("PART I - EXAMPLE : 2.3 : SOLUTION :-")
+printf("\nHeat Balance Sheet")
+printf("\nLOSSES: Boiler loss = %.3f kWh", loss_boiler)
+printf("\n Alternator loss = %.2f kWh", loss_alter)
+printf("\n Turbine loss = %.3f kWh", loss_turbine)
+printf("\n Total loss = %.2f kWh", loss_total)
+printf("\nOUTPUT: %.1f kWh", output)
+printf("\nINPUT: %.2f kWh\n", Input)
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