From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3472/CH2/EX2.1/Example2_1.sce | 31 +++++++++++++++++++++++++++++++
 3472/CH2/EX2.2/Example2_2.sce | 32 ++++++++++++++++++++++++++++++++
 3472/CH2/EX2.3/Example2_3.sce | 39 +++++++++++++++++++++++++++++++++++++++
 3 files changed, 102 insertions(+)
 create mode 100644 3472/CH2/EX2.1/Example2_1.sce
 create mode 100644 3472/CH2/EX2.2/Example2_2.sce
 create mode 100644 3472/CH2/EX2.3/Example2_3.sce

(limited to '3472/CH2')

diff --git a/3472/CH2/EX2.1/Example2_1.sce b/3472/CH2/EX2.1/Example2_1.sce
new file mode 100644
index 000000000..641f5335a
--- /dev/null
+++ b/3472/CH2/EX2.1/Example2_1.sce
@@ -0,0 +1,31 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.1 :
+// Page number 25-26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+M = 15000.0+10.0         // Water evaporated(kg)
+C = 5000.0+5.0           // Coal consumption(kg)
+time = 8.0               // Generation shift time(hours)
+
+//Calculations
+//Case(a)
+M1 = M-15000.0 
+C1 = C-5000.0 
+M_C = M1/C1                                        // Limiting value of water evaporation(kg)
+//Case(b)
+kWh = 0                                            // Station output at no load
+consumption_noload = 5000+5*kWh                    // Coal consumption at no load(kg)
+consumption_noload_hr = consumption_noload/time    // Coal consumption per hour(kg)
+
+//Results
+disp("PART I - EXAMPLE : 2.1 : SOLUTION :-")
+printf("\nCase(a): Limiting value of water evaporation per kg of coal consumed, M/C = %.f kg", M_C)
+printf("\nCase(b): Coal per hour for running station at no load = %.f kg\n", consumption_noload_hr)
diff --git a/3472/CH2/EX2.2/Example2_2.sce b/3472/CH2/EX2.2/Example2_2.sce
new file mode 100644
index 000000000..18ba2b484
--- /dev/null
+++ b/3472/CH2/EX2.2/Example2_2.sce
@@ -0,0 +1,32 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.2 :
+// Page number 26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+amount = 25.0*10**5           // Amount spent in 1 year(Rs)
+value_heat = 5000.0           // Heating value(kcal/kg)
+cost = 500.0                  // Cost of coal per ton(Rs)
+n_ther = 0.35                 // Thermal efficiency
+n_elec = 0.9                  // Electrical efficiency
+
+//Calculations
+n = n_ther*n_elec                          // Overall efficiency
+consumption = amount/cost*1000             // Coal consumption in 1 year(kg)
+combustion = consumption*value_heat        // Heat of combustion(kcal)
+output = n*combustion                      // Heat output(kcal)
+unit_gen = output/860.0                    // Annual heat generated(kWh). 1 kWh = 860 kcal
+hours_year = 365*24.0                      // Total time in a year(hour)
+load_average = unit_gen/hours_year         // Average load on the power plant(kW)
+
+//Result
+disp("PART I - EXAMPLE : 2.2 : SOLUTION :-")
+printf("\nAverage load on power plant = %.2f kW\n", load_average)
+printf("\nNOTE: ERROR: Calculation mistake in the final answer in the textbook")
diff --git a/3472/CH2/EX2.3/Example2_3.sce b/3472/CH2/EX2.3/Example2_3.sce
new file mode 100644
index 000000000..cd9d92df9
--- /dev/null
+++ b/3472/CH2/EX2.3/Example2_3.sce
@@ -0,0 +1,39 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART I : GENERATION
+// CHAPTER 2: THERMAL STATIONS
+
+// EXAMPLE : 2.3 :
+// Page number 26
+clear ; clc ; close ; // Clear the work space and console
+
+//Given data
+consumption = 0.5       // Coal consumption per kWh output(kg)
+cal_value = 5000.0      // Calorific value(kcal/kg)
+n_boiler = 0.8          // Boiler efficiency
+n_elec = 0.9            // Electrical efficiency
+
+//Calculations
+input_heat = consumption*cal_value                 // Heat input(kcal)
+input_elec = input_heat/860.0                      // Equivalent electrical energy(kWh). 1 kWh = 860 kcal
+loss_boiler = input_elec*(1-n_boiler)              // Boiler loss(kWh)
+input_steam = input_elec-loss_boiler               // Heat input to steam(kWh)
+input_alter = 1/n_elec                             // Alternator input(kWh)
+loss_alter = input_alter*(1-n_elec)                // Alternate loss(kWh)
+loss_turbine = input_steam-input_alter             // Loss in turbine(kWh)
+loss_total = loss_boiler+loss_alter+loss_turbine   // Total loss(kWh)
+output = 1.0                                       // Output(kWh)
+Input = output+loss_total                          // Input(kWh)
+
+//Results
+disp("PART I - EXAMPLE : 2.3 : SOLUTION :-")
+printf("\nHeat Balance Sheet")
+printf("\nLOSSES:  Boiler loss      = %.3f kWh", loss_boiler)
+printf("\n         Alternator loss  = %.2f kWh", loss_alter)
+printf("\n         Turbine loss     = %.3f kWh", loss_turbine)
+printf("\n         Total loss       = %.2f kWh", loss_total)
+printf("\nOUTPUT:  %.1f kWh", output)
+printf("\nINPUT:   %.2f kWh\n", Input)
-- 
cgit