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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3308/CH22/EX22.2/Ex22_2.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '3308/CH22/EX22.2/Ex22_2.sce')
| -rwxr-xr-x | 3308/CH22/EX22.2/Ex22_2.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/3308/CH22/EX22.2/Ex22_2.sce b/3308/CH22/EX22.2/Ex22_2.sce new file mode 100755 index 000000000..d2794ff75 --- /dev/null +++ b/3308/CH22/EX22.2/Ex22_2.sce @@ -0,0 +1,20 @@ +clc
+// Given that
+d=10//in mm diameter of drill bit
+f=0.2//in mm/rev feed
+N=800//in rpm spindle rotation
+
+// Sample Problem on page no. 632
+
+printf("\n # Material Removal Rate and Torque in Drilling # \n")
+
+MRR=[((3.14*(d^2))/4)*f*N]/60
+printf("\n\n Material Removal Rate %d=mm^3/sec",MRR)
+
+//Answer in the book is given 210 mm^3/sec
+
+//from the book data an average unit power of 0.5Ws/mm2 for magnesium is taken
+T=(MRR*0.5)/((N*2*3.14)/60)
+printf("\n\n Torque on the drill %f=Nm",T)
+
+
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