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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3308/CH22 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '3308/CH22')
| -rwxr-xr-x | 3308/CH22/EX22.1/Ex22_1.sce | 36 | ||||
| -rwxr-xr-x | 3308/CH22/EX22.1/Ex22_1.txt | 12 | ||||
| -rwxr-xr-x | 3308/CH22/EX22.2/Ex22_2.sce | 20 | ||||
| -rwxr-xr-x | 3308/CH22/EX22.2/Ex22_2.txt | 7 |
4 files changed, 75 insertions, 0 deletions
diff --git a/3308/CH22/EX22.1/Ex22_1.sce b/3308/CH22/EX22.1/Ex22_1.sce new file mode 100755 index 000000000..4f24bf3be --- /dev/null +++ b/3308/CH22/EX22.1/Ex22_1.sce @@ -0,0 +1,36 @@ +clc
+// Given that
+l=6//in inch Length of rod
+di=1/2//in inch initial diameter of rod
+df=0.480//in inch final diameter of rod
+N=400//in rpm spindle rotation
+Vt=8//in inch/minute axial speed of the tool
+
+// Sample Problem on page no. 600
+
+printf("\n # Material Removal Rate and Cutting Force in Turning # \n")
+
+V=3.14*di*N
+printf("\n\n Cutting speed=%d in/min",V)
+
+v1=3.14*df*N//cutting speed from machined diameter
+d=(di-df)/2//depth of cut
+f=Vt/N//feed
+Davg=(di+df)/2
+MRR=3.14*Davg*d*f*N
+printf("\n\n Material Removal Rate %f=in^3/min",MRR)
+
+t=l/(f*N)
+printf("\n\n Cutting time=%f min",t)
+
+P=(4/2.73)*MRR//average value of stainless steel is taken as 4 ws/mm3 or 4/2.73 hpmin/mm3
+printf("\n\n Cutting power=%f hp",P)
+
+Fc=((P*396000)/(N*2*3.14))/(Davg/2)
+printf("\n\n Cutting force=%d lb",Fc)
+
+//answer in the book is given 118 lb due to approximation
+
+
+
+
diff --git a/3308/CH22/EX22.1/Ex22_1.txt b/3308/CH22/EX22.1/Ex22_1.txt new file mode 100755 index 000000000..9b0ca6b2e --- /dev/null +++ b/3308/CH22/EX22.1/Ex22_1.txt @@ -0,0 +1,12 @@ + # Material Removal Rate and Cutting Force in Turning #
+
+
+ Cutting speed=628 in/min
+
+ Material Removal Rate 0.123088=in^3/min
+
+ Cutting time=0.750000 min
+
+ Cutting power=0.180349 hp
+
+ Cutting force=116 lb
\ No newline at end of file diff --git a/3308/CH22/EX22.2/Ex22_2.sce b/3308/CH22/EX22.2/Ex22_2.sce new file mode 100755 index 000000000..d2794ff75 --- /dev/null +++ b/3308/CH22/EX22.2/Ex22_2.sce @@ -0,0 +1,20 @@ +clc
+// Given that
+d=10//in mm diameter of drill bit
+f=0.2//in mm/rev feed
+N=800//in rpm spindle rotation
+
+// Sample Problem on page no. 632
+
+printf("\n # Material Removal Rate and Torque in Drilling # \n")
+
+MRR=[((3.14*(d^2))/4)*f*N]/60
+printf("\n\n Material Removal Rate %d=mm^3/sec",MRR)
+
+//Answer in the book is given 210 mm^3/sec
+
+//from the book data an average unit power of 0.5Ws/mm2 for magnesium is taken
+T=(MRR*0.5)/((N*2*3.14)/60)
+printf("\n\n Torque on the drill %f=Nm",T)
+
+
diff --git a/3308/CH22/EX22.2/Ex22_2.txt b/3308/CH22/EX22.2/Ex22_2.txt new file mode 100755 index 000000000..c0063062b --- /dev/null +++ b/3308/CH22/EX22.2/Ex22_2.txt @@ -0,0 +1,7 @@ +
+ # Material Removal Rate and Torque in Drilling #
+
+
+ Material Removal Rate 209=mm^3/sec
+
+ Torque on the drill 1.250000=Nm
\ No newline at end of file |