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authorpriyanka2015-06-24 15:03:17 +0530
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+clc
+// Given that
+alpha = 10 // Rake angle of tool in Degree
+v = 200 // Cutting speed in m/min
+t1 = 0.2 // Uncut thickness in mm
+w = 2 // Width of cut in mm
+mu = 0.5 // Avg value of the cofficient of tbe friction
+T_S = 400 // Shear stress of the work material in N/mm^2
+Cm = 70 // Machining constant in Degree
+// Sample Problem 4 on page no. 194
+printf("\n # PROBLEM 4.4 # \n")
+lambda = atand(mu)
+phi = (Cm + alpha - lambda)/2
+Fs = (w*t1*T_S)/(sind(phi))
+R = Fs/(cosd(phi+lambda-alpha))
+Fc = R*(cosd(lambda-alpha))
+Ft = R*(sind(lambda-alpha))
+// Using Lee and Shaffer relation
+phi_ = 45-lambda+alpha
+Fs_ = (w*t1*T_S)/(sind(phi_))
+R_ = Fs_/(cosd(phi_+lambda-alpha))
+Fc_ = R_*(cosd(lambda-alpha))
+Ft_ = R_*(sind(lambda-alpha))
+printf("\n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N \n Using Lee and Shaffer relation- \n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N,",phi,Fc,Ft,phi_,Fc_,Ft_)
+// Answer in the book for cutting force is given as 486.9 N and for thrust force is given as 144.9 N , When using Lee and Shaffer relation answer in the book for cutting force is given as 481.9 N and for trust force is given as 160.6 N