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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3250/CH4/EX4.4/Ex4_4.sce | |
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initial commit / add all books
Diffstat (limited to '3250/CH4/EX4.4/Ex4_4.sce')
-rwxr-xr-x | 3250/CH4/EX4.4/Ex4_4.sce | 25 |
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diff --git a/3250/CH4/EX4.4/Ex4_4.sce b/3250/CH4/EX4.4/Ex4_4.sce new file mode 100755 index 000000000..319c7254a --- /dev/null +++ b/3250/CH4/EX4.4/Ex4_4.sce @@ -0,0 +1,25 @@ +clc +// Given that +alpha = 10 // Rake angle of tool in Degree +v = 200 // Cutting speed in m/min +t1 = 0.2 // Uncut thickness in mm +w = 2 // Width of cut in mm +mu = 0.5 // Avg value of the cofficient of tbe friction +T_S = 400 // Shear stress of the work material in N/mm^2 +Cm = 70 // Machining constant in Degree +// Sample Problem 4 on page no. 194 +printf("\n # PROBLEM 4.4 # \n") +lambda = atand(mu) +phi = (Cm + alpha - lambda)/2 +Fs = (w*t1*T_S)/(sind(phi)) +R = Fs/(cosd(phi+lambda-alpha)) +Fc = R*(cosd(lambda-alpha)) +Ft = R*(sind(lambda-alpha)) +// Using Lee and Shaffer relation +phi_ = 45-lambda+alpha +Fs_ = (w*t1*T_S)/(sind(phi_)) +R_ = Fs_/(cosd(phi_+lambda-alpha)) +Fc_ = R_*(cosd(lambda-alpha)) +Ft_ = R_*(sind(lambda-alpha)) +printf("\n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N \n Using Lee and Shaffer relation- \n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N,",phi,Fc,Ft,phi_,Fc_,Ft_) +// Answer in the book for cutting force is given as 486.9 N and for thrust force is given as 144.9 N , When using Lee and Shaffer relation answer in the book for cutting force is given as 481.9 N and for trust force is given as 160.6 N |